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dicthelpers.diff: compare against default for missing values...
dicthelpers.diff: compare against default for missing values This is not only a bit faster, but also aligns with callers' expectations better since we can legitimately have manifestdict's _flags set to '' instead of unset. hg perfmergecalculate -r . before: ! wall 0.139582 comb 0.140000 user 0.140000 sys 0.000000 (best of 59) after: ! wall 0.126154 comb 0.120000 user 0.120000 sys 0.000000 (best of 74) hg perfmergecalculate -r .^ before: ! wall 0.236333 comb 0.240000 user 0.240000 sys 0.000000 (best of 36) after: ! wall 0.212265 comb 0.210000 user 0.210000 sys 0.000000 (best of 45)

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r18894:ed46c2b9 default
r18894:ed46c2b9 default
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dicthelpers.py
55 lines | 1.6 KiB | text/x-python | PythonLexer
# dicthelpers.py - helper routines for Python dicts
#
# Copyright 2013 Facebook
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.
def diff(d1, d2, default=None):
'''Return all key-value pairs that are different between d1 and d2.
This includes keys that are present in one dict but not the other, and
keys whose values are different. The return value is a dict with values
being pairs of values from d1 and d2 respectively, and missing values
treated as default, so if a value is missing from one dict and the same as
default in the other, it will not be returned.'''
res = {}
if d1 is d2:
# same dict, so diff is empty
return res
for k1, v1 in d1.iteritems():
v2 = d2.get(k1, default)
if v1 != v2:
res[k1] = (v1, v2)
for k2 in d2:
if k2 not in d1:
v2 = d2[k2]
if v2 != default:
res[k2] = (default, v2)
return res
def join(d1, d2, default=None):
'''Return all key-value pairs from both d1 and d2.
This is akin to an outer join in relational algebra. The return value is a
dict with values being pairs of values from d1 and d2 respectively, and
missing values represented as default.'''
res = {}
for k1, v1 in d1.iteritems():
if k1 in d2:
res[k1] = (v1, d2[k1])
else:
res[k1] = (v1, default)
if d1 is d2:
return res
for k2 in d2:
if k2 not in d1:
res[k2] = (default, d2[k2])
return res