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bisect: refer directly to bisect() revset predicate in help...

bisect: refer directly to bisect() revset predicate in help We have specific syntax for displaying the help text for a particular revset predicate, so let's refer directly to the bisect() revset in the verbose bisect help. It seems likely that the user doesn't care about other revsets at that point, so they will probably not miss the text about the other revset predicates.

Maciej Fijalkowski - - Load All Authors

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      #ifndef _HG_BDIFF_H_

      #define _HG_BDIFF_H_

      struct bdiff_line {

      	int hash, n, e;

      	ssize_t len;

      	const char *l;

      };

      struct bdiff_hunk;

      struct bdiff_hunk {

      	int a1, a2, b1, b2;

      	struct bdiff_hunk *next;

      };

      int bdiff_splitlines(const char *a, ssize_t len, struct bdiff_line **lr);

      int bdiff_diff(struct bdiff_line *a, int an, struct bdiff_line *b, int bn,

      	struct bdiff_hunk *base);

      void bdiff_freehunks(struct bdiff_hunk *l);

      #endif

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				#ifndef _HG_BDIFF_H_
				#define _HG_BDIFF_H_

				struct bdiff_line {
				int hash, n, e;
				ssize_t len;
				const char *l;
				};

				struct bdiff_hunk;
				struct bdiff_hunk {
				int a1, a2, b1, b2;
				struct bdiff_hunk *next;
				};

				int bdiff_splitlines(const char a, ssize_t len, struct bdiff_line *lr);
				int bdiff_diff(struct bdiff_line a, int an, struct bdiff_line b, int bn,
				struct bdiff_hunk *base);
				void bdiff_freehunks(struct bdiff_hunk *l);

				#endif