##// END OF EJS Templates
time(it) magic: reorganize time formatting code...
Jan Schulz -
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@@ -1076,22 +1076,6 b' def parse_breakpoint(text, current_file):'
1076 def _format_time(timespan, precision=3):
1076 def _format_time(timespan, precision=3):
1077 """Formats the timespan in a human readable form"""
1077 """Formats the timespan in a human readable form"""
1078 import math
1078 import math
1079 # XXX: Unfortunately the unicode 'micro' symbol can cause problems in
1080 # certain terminals.
1081 # See bug: https://bugs.launchpad.net/ipython/+bug/348466
1082
1083 # This is trying to prevent crashes, so it's more secure than it needs to
1084 # E.g. eclipse is able to print a µ, but has no sys.stdout.encoding set.
1085
1086
1087 units = [u"s", u"ms",u'us',"ns"] # the save value
1088 if hasattr(sys.stdout, 'encoding') and sys.stdout.encoding:
1089 try:
1090 u'\xb5'.encode(sys.stdout.encoding)
1091 units = [u"s", u"ms",u'\xb5s',"ns"]
1092 except:
1093 pass
1094 scaling = [1, 1e3, 1e6, 1e9]
1095
1079
1096 if timespan >= 60.0:
1080 if timespan >= 60.0:
1097 # we have more than a minute, format that in a human readable form
1081 # we have more than a minute, format that in a human readable form
@@ -1107,7 +1091,22 b' def _format_time(timespan, precision=3):'
1107 if leftover < 1:
1091 if leftover < 1:
1108 break
1092 break
1109 return " ".join(time)
1093 return " ".join(time)
1094
1110
1095
1096 # Unfortunately the unicode 'micro' symbol can cause problems in
1097 # certain terminals.
1098 # See bug: https://bugs.launchpad.net/ipython/+bug/348466
1099 # Try to prevent crashes by being more secure than it needs to
1100 # E.g. eclipse is able to print a µ, but has no sys.stdout.encoding set.
1101 units = [u"s", u"ms",u'us',"ns"] # the save value
1102 if hasattr(sys.stdout, 'encoding') and sys.stdout.encoding:
1103 try:
1104 u'\xb5'.encode(sys.stdout.encoding)
1105 units = [u"s", u"ms",u'\xb5s',"ns"]
1106 except:
1107 pass
1108 scaling = [1, 1e3, 1e6, 1e9]
1109
1111 if timespan > 0.0:
1110 if timespan > 0.0:
1112 order = min(-int(math.floor(math.log10(timespan)) // 3), 3)
1111 order = min(-int(math.floor(math.log10(timespan)) // 3), 3)
1113 else:
1112 else:
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