support 'foo*??' in lexer

'??foo*' already worked

IPython/lib/lexers.py

@@ -62,6 +62,7 b' ipython_tokens = ['
   (r'^(!!)(.+)(\n)', bygroups(Operator, using(BashLexer), Text)),
   (r'(!)(?!=)(.+)(\n)', bygroups(Operator, using(BashLexer), Text)),
   (r'^(\s*)(\?\??)(\s*%{0,2}[\w\.\*]*)', bygroups(Text, Operator, Text)),
+  (r'(\s*%{0,2}[\w\.\*]*)(\?\??)(\s*)$', bygroups(Text, Operator, Text)),
 ]
 
 def build_ipy_lexer(python3):

IPython/lib/tests/test_lexers.py

@@ -120,3 +120,11 b' class TestLexers(TestCase):'
             (Token.Text, '\n'),
         ]
         self.assertEqual(tokens_2, list(self.lexer.get_tokens(fragment_2)))
+
+        fragment = ' *int*?\n'
+        tokens = [
+            (Token.Text, ' *int*'),
+            (Token.Operator, '?'),
+            (Token.Text, '\n'),
+        ]
+        self.assertEqual(tokens, list(self.lexer.get_tokens(fragment)))