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backout: use commonancestorsheads for checking linear heritage...
backout: use commonancestorsheads for checking linear heritage If two revisions are linearly related, there will only be one ancestor, and commonancestors and commonancestorsheads would give the same result. commonancestorsheads is however slightly simpler, faster and more correct.

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r10263:25e57239 stable
r21105:12312f06 default
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strutil.py
34 lines | 913 B | text/x-python | PythonLexer
Vadim Gelfer
fix issue 322....
r2953 # strutil.py - string utilities for Mercurial
#
# Copyright 2006 Vadim Gelfer <vadim.gelfer@gmail.com>
#
Martin Geisler
updated license to be explicit about GPL version 2
r8225 # This software may be used and distributed according to the terms of the
Matt Mackall
Update license to GPLv2+
r10263 # GNU General Public License version 2 or any later version.
Vadim Gelfer
fix issue 322....
r2953
def findall(haystack, needle, start=0, end=None):
if end is None:
end = len(haystack)
if end < 0:
end += len(haystack)
if start < 0:
start += len(haystack)
while start < end:
c = haystack.find(needle, start, end)
if c == -1:
break
yield c
start = c + 1
def rfindall(haystack, needle, start=0, end=None):
if end is None:
end = len(haystack)
if end < 0:
end += len(haystack)
if start < 0:
start += len(haystack)
while end >= 0:
c = haystack.rfind(needle, start, end)
if c == -1:
break
yield c
end = c - 1