##// END OF EJS Templates
backout: use commonancestorsheads for checking linear heritage...
backout: use commonancestorsheads for checking linear heritage If two revisions are linearly related, there will only be one ancestor, and commonancestors and commonancestorsheads would give the same result. commonancestorsheads is however slightly simpler, faster and more correct.

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r21105:12312f06 default
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strutil.py
34 lines | 913 B | text/x-python | PythonLexer
# strutil.py - string utilities for Mercurial
#
# Copyright 2006 Vadim Gelfer <vadim.gelfer@gmail.com>
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.
def findall(haystack, needle, start=0, end=None):
if end is None:
end = len(haystack)
if end < 0:
end += len(haystack)
if start < 0:
start += len(haystack)
while start < end:
c = haystack.find(needle, start, end)
if c == -1:
break
yield c
start = c + 1
def rfindall(haystack, needle, start=0, end=None):
if end is None:
end = len(haystack)
if end < 0:
end += len(haystack)
if start < 0:
start += len(haystack)
while end >= 0:
c = haystack.rfind(needle, start, end)
if c == -1:
break
yield c
end = c - 1