peer: stop having a `peer()` method on `peer()`

This is already a peer, why do you want a peer if you already have one.

mercurial/hg.py

@@ -723,8 +723,6 b' def clone('
             srcpeer = source
         branches = (None, branch or [])
         # XXX path: simply use the peer `path` object when this become available
-        srcpeer = source.peer()  # in case we were called with a localrepo
-        branches = (None, branch or [])
         origsource = source = srcpeer.url()
     srclock = destlock = destwlock = cleandir = None
     destpeer = None

mercurial/httppeer.py

@@ -403,9 +403,6 b' class httppeer(wireprotov1peer.wirepeer)'
     def local(self):
         return None
 
-    def peer(self):
-        return self
-
     def canpush(self):
         return True
 

mercurial/interfaces/repository.py

@@ -123,12 +123,6 b' class ipeerconnection(interfaceutil.Inte'
         can be used to interface with it. Otherwise returns ``None``.
         """
 
-    def peer():
-        """Returns an object conforming to this interface.
-
-        Most implementations will ``return self``.
-        """
-
     def canpush():
         """Returns a boolean indicating if this peer can be pushed to."""
 

mercurial/localrepo.py

@@ -325,9 +325,6 b' class localpeer(repository.peer):'
     def local(self):
         return self._repo
 
-    def peer(self):
-        return self
-
     def canpush(self):
         return True
 

mercurial/sshpeer.py

@@ -416,9 +416,6 b' class sshv1peer(wireprotov1peer.wirepeer'
     def local(self):
         return None
 
-    def peer(self):
-        return self
-
     def canpush(self):
         return True