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hgwebdir: ignore hgrc parse errors while building the index page...
Alexis S. L. Carvalho -
r5332:b0bfe087 default
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@@ -139,8 +139,9 b' class hgwebdir(object):'
139 139 u = ui.ui(parentui=parentui)
140 140 try:
141 141 u.readconfig(os.path.join(path, '.hg', 'hgrc'))
142 except IOError:
143 pass
142 except Exception, e:
143 u.warn(_('error reading %s/.hg/hgrc: %s\n' % (path, e)))
144 continue
144 145 def get(section, name, default=None):
145 146 return u.config(section, name, default, untrusted=True)
146 147
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