show: use revlog function to compute length of the longest shortest node

As the core part of shortest() was extracted at 448725a2ef73, we no logner
need a templater.

hgext/show.py

@@ -28,7 +28,10 b' The following config options can influen'
 from __future__ import absolute_import
 
 from mercurial.i18n import _
-from mercurial.node import nullrev
+from mercurial.node import (
+    hex,
+    nullrev,
+)
 from mercurial import (
     cmdutil,
     commands,
@@ -440,17 +443,11 b' def longestshortest(repo, revs, minlen=4'
     If we fail to do this, a value of e.g. ``10023`` could mean either
     revision 10023 or node ``10023abc...``.
     """
-    tres = formatter.templateresources(repo.ui, repo)
-    tmpl = formatter.maketemplater(repo.ui, '{shortest(node, %d)}' % minlen,
-                                   resources=tres)
-
-    lens = [minlen]
-    for rev in revs:
-        ctx = repo[rev]
-        shortest = tmpl.render({'ctx': ctx, 'node': ctx.hex()})
-        lens.append(len(shortest))
-
-    return max(lens)
+    if not revs:
+        return minlen
+    # don't use filtered repo because it's slow. see templater.shortest().
+    cl = repo.unfiltered().changelog
+    return max(len(cl.shortest(hex(cl.node(r)), minlen)) for r in revs)
 
 # Adjust the docstring of the show command so it shows all registered views.
 # This is a bit hacky because it runs at the end of module load. When moved