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bdiff: balance recursion to avoid quadratic behavior (issue4704)...
Matt Mackall -
r29014:f1ca2496 stable
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@@ -0,0 +1,29 b''
1 #require no-pure
2
3 A script to generate nasty diff worst-case scenarios:
4
5 $ cat > s.py <<EOF
6 > import random
7 > for x in xrange(100000):
8 > print
9 > if random.randint(0, 100) >= 50:
10 > x += 1
11 > print hex(x)
12 > EOF
13
14 $ hg init a
15 $ cd a
16
17 Check in a big file:
18
19 $ python ../s.py > a
20 $ hg ci -qAm0
21
22 Modify it:
23
24 $ python ../s.py > a
25
26 Time a check-in, should never take more than 10 seconds user time:
27
28 $ hg ci --time -m1
29 time: real .* secs .user [0-9][.].* sys .* (re)
@@ -148,7 +148,7 b' static int equatelines(struct line *a, i'
148 148 static int longest_match(struct line *a, struct line *b, struct pos *pos,
149 149 int a1, int a2, int b1, int b2, int *omi, int *omj)
150 150 {
151 int mi = a1, mj = b1, mk = 0, mb = 0, i, j, k;
151 int mi = a1, mj = b1, mk = 0, mb = 0, i, j, k, half = (a1 + a2) / 2;
152 152
153 153 for (i = a1; i < a2; i++) {
154 154 /* skip all lines in b after the current block */
@@ -165,8 +165,9 b' static int longest_match(struct line *a,'
165 165 pos[j].pos = i;
166 166 pos[j].len = k;
167 167
168 /* best match so far? */
169 if (k > mk || (k == mk && i <= mi)) {
168 /* best match so far? we prefer matches closer
169 to the middle to balance recursion */
170 if (k > mk || (k == mk && (i <= mi || i < half))) {
170 171 mi = i;
171 172 mj = j;
172 173 mk = k;
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